031. Technical interview question: Print each elements in an array of ints

1. void printArray( int arr[], int size )
2. {
3. const int N = 10;
4. int j;
5. for ( j=0; j<size; j++ ) {
6. printf("%4d ", arr[j] );
7. if ( j % N == N-1 )
8. printf("\n");
9. }
10. }
11. int main(int argc, char *argv[])
12. {
13. int x[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
14. 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
15. 21, 22, 23, 24, 25, 26, 27, 28, 29, 30,
16. 31, 32, 33, 34, 35, 36, 37, 38, 39, 40 };
17. printArray( x, 40 );
18. printf("\n");
19. return 0;
20. }

void printArray( int arr[], int size )
{
  const int N = 10;
  int j; 
  for ( j=0; j<size; j++ )  {
         printf("%4d ", arr[j] );  
    if ( j % N == N-1 )
            printf("\n");
        }
}
int main(int argc, char *argv[])
{
  int x[] = { 1,  2,  3,  4,  5,  6,  7,  8,  9, 10,
             11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
             21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 
             31, 32, 33, 34, 35, 36, 37, 38, 39, 40 };
  printArray( x, 40 ); 
  printf("\n");
  return 0;
}