031. Technical interview question: Print each elements in an array of ints

void printArray( int arr[], int size )
{
  const int N = 10;
  int j; 
  for ( j=0; j<size; j++ )  {
         printf("%4d ", arr[j] );  
    if ( j % N == N-1 )
            printf("\n");
        }
}
int main(int argc, char *argv[])
{
  int x[] = { 1,  2,  3,  4,  5,  6,  7,  8,  9, 10,
             11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
             21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 
             31, 32, 33, 34, 35, 36, 37, 38, 39, 40 };
  printArray( x, 40 ); 
  printf("\n");
  return 0;
}